数学1A_002 - slow-starter

pythonを使いつつ、数学1Aの基礎を復習

代表的な角(30°,45°,60°)の三角比(sin,cos,tan)

import numpy as np

print("-"*50)
# --------------------------------------------------
## √2、√3の計算
root2 = np.sqrt(2)
print(root2)
# 1.41421356237
root3 = np.sqrt(3)
print(root3)
# 1.73205080757

print("-"*50)
# --------------------------------------------------
## 代表的な角(30°,45°,60°)の三角比(sin)
print("sin30° = 1/2")
# sin30° = 1/2
print(np.sin(np.radians(30)))
print(1/2)
# 0.5

print("sin45° = 1/√2")
# sin45° = 1/√2
print(np.sin(np.radians(45)))
print(1/root2)
# 0.707106781187

print("sin60° = √3/2")
# sin60° = √3/2
print(np.sin(np.radians(60)))
print(root3/2)
# 0.866025403784

print("-"*50)
# --------------------------------------------------
## 代表的な角(30°,45°,60°)の三角比(cos)
print("cos30° = √3/2")
# cos30° = √3/2
print(np.cos(np.radians(30)))
print(root3/2)
# 0.866025403784

print("cos45° = 1/√2")
# cos45° = 1/√2
print(np.cos(np.radians(45)))
print(1/root2)
# 0.707106781187

print("sin60° = 1/2")
# sin60° = 1/2
print(np.cos(np.radians(60)))
print(1/2)
# 0.5

print("-"*50)
# --------------------------------------------------
## 代表的な角(30°,45°,60°)の三角比(tan)
print("tan30° = 1/√3")
# tan30° = 1/√3
print(np.tan(np.radians(30)))
print(1/root3)
# 0.57735026919

print("tan45° = 1/√2")
# tan45° = 1
print(np.tan(np.radians(45)))
print(1/1)
# 1.0

print("tan60° = √3")
# tan60° = √3
print(np.tan(np.radians(60)))
print(root3)
# 1.73205080757